Answer
$\lim\limits_{x \to 0} f(x)$ = 4.
Work Step by Step
$\lim\limits_{x \to 0} 4-x^{2}$ $\leq$ $\lim\limits_{x \to 0} f(x)$ $\leq$$\lim\limits_{x \to 0} 4+x^{2}$
4$\leq$ $\lim\limits_{x \to 0} f(x)$$\leq$4
Therefore, $\lim\limits_{x \to 0} f(x)$ = 4.
