Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 68: 92

Answer

$$\lim_{x \to 0}f(x)=0$$

Work Step by Step

Looking at the graph, we find that the function $f(x)=|x|\cos x$ is squeezed between $|x|$ and $-|x|$, $-|x| \le |x| \cos x\le |x|$, over some interval containing $x=0$. We also find that$$\lim_{x \to 0}-|x|= \lim_{x \to 0}|x|=0 .$$Thus, by applying the Squeeze Theorem we conclude that$$\lim_{x \to 0}f(x)= \lim_{x \to 0}|x| \cos x=0.$$
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