Answer
$\lim\limits_{x\to 0}\dfrac{\sin^2{x}}{x}=0.$
Work Step by Step
$\lim\limits_{x\to 0}\dfrac{\sin^2{x}}{x}=\lim\limits_{x\to 0}\dfrac{\sin{x}}{x}\times\lim\limits_{x\to 0}\sin{x}=(1)(0)=0.$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 1 - Limits and Their Properties - 1.3 Exercises - Page 68: 67
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