Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 1 - Limits and Their Properties - 1.4 Exercises - Page 79: 8

Answer

$\lim\limits_{x\to2^-}\dfrac{2}{x+2}=\dfrac{1}{2}.$

Work Step by Step

Using direct substitution: $\lim\limits_{x\to2^-}\dfrac{2}{x+2}=\dfrac{2}{2+2}=\dfrac{1}{2}.$
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