Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter P - P.3 - Functions and Their Graphs - Exercises - Page 29: 72

Answer

$0.36\times\pi\times t^{2}$

Work Step by Step

The notation can be rewritten as $A(r(t))$. This can be found by substituting the function, r(t) into A(r). $A(r)=\pi \times r^{2}$ , $r(t)=0.6t$, Therefore $A(r(t))=\pi \times (r(t))^{2}$ $=\pi \times (0.6\times t)^{2}$ =$0.36\times\pi\times t^{2}$ The meaning of this expression is the rate of change of the area of circle per second, $t$
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