Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter P - P.3 - Functions and Their Graphs - Exercises - Page 29: 86

Answer

$y=-\sqrt{36-x^2}$

Work Step by Step

The equation of the bottom half of the circle can be found by taking the equation of the circle and excluding all of the positive y-values. In order to see how this works let's rewrite the equation: $x^2+y^2=36$ $y^2=36-x^2$ $y=±\sqrt{36-x^2}$ After taking the square root of both sides, we can see that see that the equation of the circle has both positive and negative y-values. Let's remove the positive sign to end up with only the bottom half of the circle. $y=-\sqrt{36-x^2}$
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