Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter P - Review Exercises - Page 37: 34

Answer

(a) $C=22.75t+36,500$ (b) $R=30t$ (c) $t=5034.48$ hours

Work Step by Step

Let $t$ be the hours of operation of the equipment. (a) We know that it costs \$9.25 an hour for fuel and maintenance. This can be represented as $9.25t$. We know also that the equipment operator is paid \$13.50 an hour. This can be represented as $13.5t$. Finally, the equipment was purchased for \$36,500. Adding all of these costs together, we get \begin{align*} C&=9.25t+13.5t+36,500\\ &=22.75t+36,500 &&\text{(combine like terms)} \end{align*} (b) We know the customer is charged \$30 per hour that the machine is in use. This can be represented as $30t$. Thus, $R=30t$. (c) The break-even point is found by finding $t$ when $R=C$. So, we have \begin{align*} R&=C\\ 30t&=22.75t+36,500 &&\text{(substitute equations)}\\ 7.25t&=36,500 &&\text{(subtract $22.75t$)}\\ t&=5034.48 &&\text{(divide by 7.25)}\\ \end{align*}
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