Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter P - Review Exercises - Page 37: 38

Answer

$\frac{2(x+1)}{x-1}$

Work Step by Step

$f(x)=2x-6$ $\frac{f(x)-f(-1)}{x-1}$ $=\frac{(2x-6)-(2(-1)-6)}{x-1}$ $=\frac{2x-6+8}{x-1}$ $=\frac{2x+2}{x-1}$ $=\frac{2(x+1)}{x-1}$
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