Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter P - Review Exercises - Page 37: 42

Answer

Domain: All real numbers $x$ such that $x\ne-1$ Range: All real numbers $y$ such that $y\ne0$

Work Step by Step

Since the denominator must not be zero: $x+1\ne0$ $x\ne-1$ So the domain is all real numbers except -1 The range of the rational function $h(x)=\frac{1}{x}$ is all real numbers except 0 So the range of $h(x)=\frac{2}{x+1}$ is also all real numbers except 0
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