Answer
$ y=0$
Work Step by Step
Given $$ y=x^{2}-6 x+9$$
So, we have
\begin{aligned} y&=x^{2}-6 x+9\\
&=(x-3)(x-3)\\
&=(x-3)^2 \\
\end{aligned}
The smallest value for a square power is zero.
So, we see that $ y=0$ is the minimum, when $ x=3$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 1 - Precalculus Review - 1.2 Linear and Quadratic Functions - Exercises - Page 19: 37
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