Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 1 - Precalculus Review - 1.3 The Basic Classes of Functions - Exercises - Page 22: 10

Answer

$ R-\{-1\}$

Work Step by Step

Since $ s+1=0\Longrightarrow s=-1$, hence $\frac{s}{s+1}$ is not defined when $ s=-1$. Thus the domain of $ F $ is $ R-\{-1\}$.
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