Answer
$$ x\in [0,3) \cup (3, \infty).$$
Work Step by Step
We see that $\sqrt{x}$ is defined for all $ x\geq 0$. Moreover, $$ x^2-9=0 \Longrightarrow x=\pm 3.$$
Thus the domain of $ f $ is $$ x\in [0,3) \cup (3, \infty).$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 1 - Precalculus Review - 1.3 The Basic Classes of Functions - Exercises - Page 22: 8
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