Answer
$ R- \{-4,0,3\}$.
Work Step by Step
We see that $ x^{-1}=\frac{1}{x}$ is not defined at $ x=0$. Also $(x-3)(x+4)=0$ at $ x=3$ or $ x=-4$. Hence, the domain of $ f $ is $ R- \{-4,0,3\}$ (all real numbers except $-4$, $0$, and $3$).
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 1 - Precalculus Review - 1.3 The Basic Classes of Functions - Exercises - Page 22: 12
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