Answer
$ R-\{0,1\}$.
Work Step by Step
Since $ x^{-4}=\frac{1}{x^4}$, then $ x\neq 0$. Also, $(x-1)^{-3}=\frac{1}{(x-1)^3}$, so $ x\neq 1$. Hence, the domain of $ f $ is $ R-\{0,1\}$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 1 - Precalculus Review - 1.3 The Basic Classes of Functions - Exercises - Page 22: 9
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