Chapter 1 - Functions and Limits - 1.1 Four Ways to Represent a Function - 1.1 Exercises - Page 21: 27

$-3-h$

$f(x)=4+3x-x^{2}$ Lets evaluate $\frac{f(3+h)-f(3)}{h}$ $\frac{f(3+h)-f(3)}{h}$=$\frac{4+3(3+h)-(3+h)^{2}-(4+3\times3-3^{2})}{h}$ =$\frac{4+9+3h-(9+6h+h^{2})-4}{h}$=$\frac{+9+3h-9-6h-h^{2})}{h}$=$\frac{-3h-h^{2})}{h}$= $-3-h$