Chapter 1 - Functions and Limits - 1.1 Four Ways to Represent a Function - 1.1 Exercises - Page 21: 43

$f(-3) = -2$ $f(0) = 0$ $f(2) = 4$ and the graph is in the picture.

if $x\leq-1$ then $f(x)=x+1$ if $x\gt-1$ then $f(x)=x^{2}$ So $-3\leq-1$ so $f(-3) =-3+1 = -2$ $0 \gt -1$ so $f(0) =0^{2} = 0$ $2 \gt -1$ so $f(2) = 2^{2} = 4$ and the graph is in the picture.