Answer
{ x | -2 $\leq$ x $\leq$ 3}
Work Step by Step
Since $\sqrt x$ is valid only if x $\geq$ 0, we must have:
3 - t $\geq$ 0
3 $\geq$ t
t $\leq$ 3
and
2 + t $\geq$ 0
t $\geq$ -2
We conclude that: { x | -2 $\leq$ x $\leq$ 3}
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