Answer
$-10$
Work Step by Step
$\lim\limits_{t \to -3}\frac{t^2-4t-21}{t+3}=\lim\limits_{t \to -3}\frac{(t-7)(t+3)}{t+3}=\lim\limits_{t \to -3}(t-7)=(-3)-7=-10$
Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition
by LaTorre, Donald R.; Kenelly, John W.; Reed, Iris B.; Carpenter, Laurel R.; Harris, Cynthia R.
Published by
Brooks Cole
ISBN 10:
1-43904-957-2
ISBN 13:
978-1-43904-957-0
Chapter 1 - Ingredients of Change: Functions and Limits - 1.3 Activities - Page 31: 28
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