Calculus Concepts: An Informal Approach to the Mathematics of Change 5th Edition

Published by Brooks Cole
ISBN 10: 1-43904-957-2
ISBN 13: 978-1-43904-957-0

Chapter 1 - Ingredients of Change: Functions and Limits - 1.3 Activities - Page 31: 30

Answer

There is no such limit.

Work Step by Step

$\lim\limits_{x \to 2}\frac{2x^3-2x^2+x}{4x-x^3}=\lim\limits_{x \to 2}\frac{2x^2-2x+1}{4-x^2}$ Since $2x^2-2x+1$ is unfactorable and $\lim\limits_{x \to 2}4-x^2=0$, the limit does not exist.
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