Answer
$(-\infty,0)$ and any interval included in it
$(0,\infty)$ and any interval included in it
Work Step by Step
We are given the function:
$f(x)=\dfrac{1}{x^2}$
We graph the function.
The domain of $f$ is $(-\infty,0)\cup(0,\infty)$.
The range of $f$ is $(0,\infty)$.
Using the Horizontal Line Test we notice that any horizontal line in the range of the function intersects the graph in two points. Therefore the function $f$ doesn't have an inverse on $(-\infty,\infty)$.
We determine a restriction of the function's domain on which the function has an inverse:
$(-\infty,0)$ and any interval included in it
$(0,\infty)$ and any interval included in it
