Answer
$f^{-1}(x) = \dfrac{x+4}{3}$
Work Step by Step
$f(x) = 3x-4$ which means $y = 3x-4$
To find the inverse, we can interchange $x$ and $y$: $x = 3y-4$
Solving for $y$,
$y = \dfrac{x+4}{3}$
Therefore, $f^{-1}(x) = \dfrac{x+4}{3}$.
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises - Page 35: 6
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