Answer
$f^{-1}(x)=\sqrt (y-4)$
Work Step by Step
$f(x)=x^{2}+4$
$y=x^{2}+4$
$y-4=x^{2}$
$\sqrt (y-4)=x$
$f^{-1}(x)=\sqrt (y-4)$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises - Page 36: 26
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