Answer
$f^{-1}(x)=y^{2}-2$
Work Step by Step
$f(x)=\sqrt (x+2)$
$y=\sqrt (x+2)$
$y^{2}=x+2$
$y^{2}-2=x$
$f^{-1}(x)=y^{2}-2$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises - Page 36: 27
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