Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.3 Inverse, Exponential, and Logarithmic Functions - 1.3 Exercises - Page 36: 56

Answer

$x =\frac{\ln 29}{3\ln5}$

Work Step by Step

$5^{3x} = 29$ $\ln5^{3x} =\ln 29$ $3x\ln5 =\ln 29$ $3x =\frac{\ln 29}{\ln5}$ $x =\frac{\ln 29}{3\ln5}$
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