Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 76: 19

Answer

$\lim\limits_{x \to 1}{(f(x)-g(x))} =5$

Work Step by Step

$\lim\limits_{x \to 1}{(f(x)-g(x))}$ Difference: $\lim\limits_{x \to 1}{(f(x)-g(x))} = \lim\limits_{x \to 1}{f(x)} - \lim\limits_{x \to 1}{g(x)}$ We know that $ \lim\limits_{x \to 1}{f(x)} = 8$ and $ \lim\limits_{x \to 1}{g(x)} = 3$ $\lim\limits_{x \to 1}{(f(x)-g(x))} = \lim\limits_{x \to 1}{f(x)} - \lim\limits_{x \to 1}{g(x)}=8-3=5$
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