Answer
$3$
Work Step by Step
$\lim _{x\rightarrow 1}\dfrac {5x^{2}+6x+1}{8\times -4}=\dfrac {5\times 1^{2}+6\times 1+1}{8\times 1-4}=\dfrac {12}{8-4}=\dfrac {12}{4}=3$
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