Answer
$\dfrac {3}{8}=0.375$
Work Step by Step
$\lim _{h\rightarrow 0}\dfrac {3}{\sqrt {16+3h}+4}=\dfrac {3}{\sqrt {16+3\times 0}+4}=\dfrac {3}{\sqrt {16}+4}=\dfrac {3}{8}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 77: 32
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
