Answer
$100$
Work Step by Step
$\lim _{h\rightarrow 0}\dfrac {100}{\left( 10h-1\right) ^{11}+2}=\dfrac {100}{\left( 10\times 0-1\right) ^{11}+2}=\dfrac {100}{\left( -1\right) ^{11}+2}=\dfrac {100}{-1+2}=100$
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