Answer
$\dfrac {1}{2}$
Work Step by Step
$\lim _{x\rightarrow 2}\left( \dfrac {1}{x-2}-\dfrac {2}{x^{2}-2x}\right) =\dfrac {x-2}{x^{2}-2x}=\dfrac {x-2}{x\left( x-2\right) }=\dfrac {1}{x}=\dfrac {1}{2}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 2 - Limits - 2.3 Techniques for Computing Limits - 2.3 Exercises - Page 78: 64
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