Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 22: 55

Answer

$$ f(x) = \left\{ \begin{array}{2} 3-x & \quad 0 \leq x \le 3 \\ 2x-6 & \quad 3 \lt x \leq 5 \\ \end{array} \right. $$

Work Step by Step

The left line has a slope of -1 and a y-intercept of 3, so the equation of the line would be $y=-x+3$. The slope of the right line is 2 and the line is shifted to the right, from a y-intercept of 0, 3 units. So, the line's equation would be $y=2(x-3)$. Simplified, the equation is $y=2x-6$. These equations are put into a piecewise function within their domains $[0,3]$ and $(3, 5]$.
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