Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 1 - Section 1.1 - Four Ways to Represent a Function - 1.1 Exercises - Page 22: 58

Answer

Perimeter = $2A+\frac{32}{A}$, $A\gt0$

Work Step by Step

Let the lengths of the rectangle be $A$ and $B$, where $A\ne B$. Area = $AB=16$ $B=\frac{16}{A}$ Perimeter = $2A+2B=2A+\frac{32}{A}$ $\because$ lengths are positive, $A\gt0$ $B=\frac{16}{A}\gt0$
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