Answer
$ f(x)$ is even.
Work Step by Step
$f(x)$ is odd if $f(-x)=-f(x)$
$ f(x)$ is even if $f(-x)=f(x)$
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$f(x)=\displaystyle \frac{1}{x^{2}+4}$
$f(-x)=\displaystyle \frac{1}{(-x)^{2}+4}=\frac{1}{x^{2}+4}=f(x)$
$ f(x)$ is even.
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 2 - Nonlinear Functions - 2.1 Properties of Functions - 2.1 Exercises - Page 55: 67
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