Chapter 2 - Nonlinear Functions - 2.1 Properties of Functions - 2.1 Exercises - Page 55: 70

Neither.

$ f(x)$ is odd if $f(-x)=-f(x)$ $ f(x)$ is even if $f(-x)=f(x)$ ------------- $f(x)=|x-2|$ $f(-x)=|-x-2|=|-(x+2)|=|x+2|$, which does not equal either of $(-f(x))$ or $f(x)$. The function is neither odd nor even.