Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.2 - Limit of a Function and Limit Laws - Exercises 2.2 - Page 58: 75

Answer

$c=-1, 0, 1$, limits $1,0,1$.

Work Step by Step

As can be seen from the figure, clearly $f(x)$ is sandwiched between $x^2$ and $x^4$ and is confined in the shaded area; based on Sandwich Theorem, we have at $c=-1, 0, 1$, $\lim\limits_{x \to -1}f(x)=1$, $\lim\limits_{x \to 0}f(x)=0$ and $\lim\limits_{x \to 1}f(x)=1$.
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