Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.2 - Limit of a Function and Limit Laws - Exercises 2.2 - Page 58: 66

Answer

a. $1/2$ b. see graph and explanations.

Work Step by Step

a. Since $\lim\limits_{x\to 0}(\frac{1}{2}-\frac{x^2}{24})=\frac{1}{2}$, using the Sandwich Theorem of limits, we have: $\lim\limits_{x\to 0}\frac{1-cos(x)}{x^2}=\frac{1}{2}$ b. The three functions are shown in the graph. It can be seen that as x gets close to zero, all functions meet at $1/2$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.