Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.2 - Limit of a Function and Limit Laws - Exercises 2.2 - Page 57: 65

Answer

a. 1 b. see graph and explanations.

Work Step by Step

a. Since $\lim\limits_{x \to 0}(1-\frac{x^2}{6})=1$, according to the Sandwich Theorem for limits, we have $\lim\limits_{x \to 0}\frac{x\cdot sin(x)}{2-2cos(x)}=1$ b. As can be seen from the graph, all three curves approach 1 when x approaches zero. The inequalities given in the problem can also be visualized in the graph.
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