Answer
$-1$
Work Step by Step
Note that, $\lim\limits_{x \to a}\sin x=\sin a$ for all real numbers $a$. Using this along with our limit laws, we get
$\lim\limits_{x \to 0}(2\sin x -1 )=2\sin 0 -1=0-1=-1.$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 2: Limits and Continuity - Section 2.2 - Limit of a Function and Limit Laws - Exercises 2.2 - Page 57: 43
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