Answer
a) 0
b) 0
c) 9
d) 3
Work Step by Step
a.$ \lim\limits_{x \to 4}(g(x)+3) = (-3+3) =-3+3= 0$
b .$ \lim\limits_{x \to 4}[xf(x)] = (4)(0) = 0$
c. $ \lim\limits_{x \to 4}[g(x)]^{2}= (-3)^{2} = 9$
d . $ \lim\limits_{x \to 4}\dfrac{g(x)}{f(x)-1}= \dfrac{(-3)}{(0-1)} = 3$
