Answer
Even.
Work Step by Step
Even functions are, where f(-x)=f(x), here $f(x)=x^{2}+1$, $f(-x)=(-x)^{2}+1=x^{2}+1$, which are equal, threfore the function is even.
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 1 - Section 1.1 - Functions and Their Graphs - Exercises - Page 12: 49
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