Answer
The length of side $c$ is $\sqrt7$.
Work Step by Step
$$a = 2 \hspace{1cm}b=3\hspace{1cm}C=60^\circ$$
- Recall the law of cosines: $$c^2=a^2+b^2-2ab\cos C$$
Therefore, we can calculate the length of side $c$:
$$c^2=2^2+3^2-2\times2\times3\times\cos60^\circ$$
$$c^2=4+9-12\times\frac{1}{2}$$
$$c^2=13-6=7$$
$$c=\sqrt7$$ (because the length of a side of a triangle is positive)
