University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises - Page 66: 12

Answer

$\lim\limits_{x \to 2} (-x^{2} + 5x -2)$ =4

Work Step by Step

$\lim\limits_{x \to 2} (-x^{2} + 5x -2)$ = - $\lim\limits_{x \to 2}x^{2} + \lim\limits_{x \to 2} 5x - \lim\limits_{x \to 2}2$ $= -(2^{2}) + 5*2 - 2$ $= -4+10-2$ $=4$
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