Answer
$\lim\limits_{t \to 6} 8(t-5)(t-7) = -8$
Work Step by Step
$\lim\limits_{t \to 6} 8(t-5)(t-7) = \lim\limits_{t \to 6} (8t^{2} -96t +280)$
= $\lim\limits_{t \to 6}8t^{2} - \lim\limits_{t \to 6}96t +\lim\limits_{t \to 6}280$
= $8*6^{2} - 96*6 + 280$
$= -8$
