University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises - Page 66: 15

Answer

$\lim\limits_{x \to 2} \frac{(2x + 5)}{(11 - x^{3})} = 3$

Work Step by Step

$\lim\limits_{x \to 2} \frac{(2x + 5)}{(11 - x^{3})} = \frac{\lim\limits_{x \to 2}(2x + 5)}{\lim\limits_{x \to 2}(11-x^{3})}$ = $\frac{2(2) + 5}{11 - 2^{3}}$ = $\frac{9}{3}$ = 3
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.