Answer
$\lim\limits_{x \to -5}\frac{(x^{2}+3x-10)}{(x+5)} = \lim\limits_{x \to -5}(x-2) = -7$
Work Step by Step
Simplify:
$\frac{(x^{2}+3x-10)}{(x+5)} = \frac{(x-2)(x+5)}{(x+5)} = (x-2)$
Now,
$\lim\limits_{x \to -5}\frac{(x^{2}+3x-10)}{(x+5)} = \lim\limits_{x \to -5}(x-2) = -7$
