Elementary Differential Equations and Boundary Value Problems 9th Edition

Published by Wiley
ISBN 10: 0-47038-334-8
ISBN 13: 978-0-47038-334-6

Chapter 1 - Introduction - 1.3 Classification of Differential Equations - Problems - Page 25: 26

Answer

$u_{1,x}=e^{-\alpha^2t}\cos x,\ u_{1,xx}=-e^{-\alpha^2t}\sin x$ $u_{1,t}=-\alpha^2e^{-\alpha^2t}\sin x$ $\alpha^2u_{1,xx}=u_{1,t}$ $u_{2,x}=\lambda e^{-\alpha^2\lambda^2t}\cos \lambda x,\ u_{2,xx}=-\lambda^2e^{-\alpha^2\lambda^2t}\sin \lambda x$ $u_{2,t}=-\alpha^2\lambda^2e^{-\alpha^2\lambda^2 t}\sin \lambda x$ $\alpha^2u_{2,xx}=u_{2,t}$
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