Answer
$0$.
Work Step by Step
First, compute $2\cdot3\cdot2$ in $\mathbb{Z}$, which is equal to $12$. Division by $4$ leaves a remainder of $0$, so the solution in $\mathbb{Z}_4$ is $0$.
Linear Algebra: A Modern Introduction
by Poole, David
Published by
Cengage Learning
ISBN 10:
1285463242
ISBN 13:
978-1-28546-324-7
Chapter 1 - Vectors - 1.1 The Geometry and Algebra of Vectors - Exercises 1.1 - Page 17: 35
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