Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - 2.1 Functions - 2.1 Assess Your Understanding - Page 59: 120

Answer

$\left(\dfrac{-3}{2},-2\right)$

Work Step by Step

The midpoint $M$ of the line segment from $P_1(x_1,y_1)$ to $P_2(x_2,y_2)$ is: $\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$. Hence, $M=\left(\dfrac{3+(-6)}{2},\dfrac{-4+0}{2}\right)=\left(\dfrac{-3}{2},-2\right)$.
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