Answer
$(x-4)^2+(y+1)^2=3^2.$
Work Step by Step
The standard equation for a circle with radius $r$ and centre $(h,k)$ is: $(x-h)^2+(y-k)^2=r^2$.
Hence our equation: $(x-4)^2+(y-(-1))^2=3^2$, which is: $(x-4)^2+(y+1)^2=3^2.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 2 - Functions and Their Graphs - 2.1 Functions - 2.1 Assess Your Understanding - Page 59: 121
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