Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Mid-Chapter Check Point - Page 71: 21

Answer

$1.2\times 10^{-2}$

Work Step by Step

Scientific notation has the form : $A\times 10^{n}$, where A is a number between 1 and 10, $ 1\leq A<10$. $\displaystyle \frac{24\times 10^{3}}{2\times 10^{6}}=\frac{24}{2}\cdot\frac{10^{3}}{10^{6}}\quad$... use the rule:$ \displaystyle \frac{a^{m}}{a^{n}}=a^{m-n}$ $=12\times 10^{3-6}$ $=12\times 10^{-3}$ ... 12 is not between 1 and 10, multiply with $10^{-1}\cdot 10^{1}$ $=(12\cdot 10^{-1})\cdot(10^{1}\times 10^{-3})\quad$... use the rule: $a^{m}\cdot a^{n}=a^{m+n}$ = $1.2\times 10^{-2}$
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