Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Mid-Chapter Check Point - Page 71: 27

Answer

$\displaystyle \frac{11\sqrt{3}}{3}$

Work Step by Step

Rationalize the denominator using $(\sqrt{3})^{2}=3$ $\displaystyle \frac{11}{\sqrt{3}}=\frac{11}{\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}$ = $\displaystyle \frac{11\sqrt{3}}{3}$
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